A gas mixture contains 10% H2, 10% O2, 30% CO2, and the remainder is H2O by mole fraction. If half of the water vapor condenses out, what is the mole percentage of hydrogen (H2) in the remaining dry gas?

CHEMICAL ENGINEERING MCQs for PPSC, FPSC, NTS, and Pakistan government job tests. Select an option below, then read the explanation.

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Subject
CHEMICAL ENGINEERINGchemical-engineering
Published
12 Mar 2019
Last updated
28 May 2026

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Explanation

Initially, the gas mixture consists of 10% H2, 10% O2, 30% CO2, and 50% H2O. When 50% of the water condenses, the water vapor reduces to 25%, leaving 75% total gas. Removing water vapor and recalculating the mole fractions on a dry basis (excluding water) increases the H2 mole fraction to 20%.

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