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Starting from rest, a body accelerates uniformly at 5 m/s². What is the approximate distance it travels in 5 seconds?

Strength of Materials MCQs for PPSC, FPSC, NTS, and Pakistan government job tests. Select an option below, then read the explanation.

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Subject
Strength of Materialscivil-engineering-mcqs › strength-of-materials
Published
15 Jan 2019
Last updated
28 May 2026

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Explanation

Using the formula for distance under constant acceleration from rest: s = 0.5 × a × t². Here, a = 5 m/s² and t = 5 s, so s = 0.5 × 5 × (5)² = 0.5 × 5 × 25 = 62.5 meters.

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