A steel rod with a cross-sectional area of 250 mm² is fixed between two parallel walls 5 meters apart. The nuts at both ends were tightened when the rod was heated to 100°C. Given the coefficient of linear expansion for steel is 0.000012/°C and Young's modulus is 0.2 MN/mm², what is the tensile stress induced in the rod when the temperature drops to 50°C?

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Subject: Theory of Structurescivil-engineering-mcqs › theory-of-structures
Published: 17 Jan 2019
Last updated: 28 May 2026

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Explanation

When the rod cools from 100°C to 50°C, it tries to contract but is restrained by the walls, causing tensile stress. Using the formula stress = E × α × ΔT, where E = 0.2 MN/mm², α = 0.000012/°C, and ΔT = 50°C, the resulting tensile stress is 0.2 × 0.000012 × 50 = 0.00012 MN/mm² or 120 N/mm².

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