What is the formula for the stiffness of a close-coiled helical spring?

Theory of Structures MCQs for PPSC, FPSC, NTS, and Pakistan government job tests. Select an option below, then read the explanation.

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Theory of Structurescivil-engineering-mcqs › theory-of-structures
Published
17 Jan 2019
Last updated
28 May 2026

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Explanation

The stiffness (spring constant) of a close-coiled helical spring is given by the formula k = (d⁴N) / (8D³n), where d is the wire diameter, D is the coil diameter, N is the modulus of rigidity, and n is the number of active coils.

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