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- Subject
- Electromagnetic Inductionelectrical-engineering-mcqs › electromagnetic-induction
- Published
- 16 Dec 2018
- Last updated
- 28 May 2026
Explanation
Given the change in current (ΔI) is 4 A over 1 second, and the induced emf (V) is 20 volts, the inductance L is calculated using L = V / (ΔI/Δt) = 20 / 4 = 5 henries.
More Electromagnetic Induction MCQs
Practice related questions from the same subject.
- 1.Can the left-hand generator rule be used to identify the polarity of an induced voltage?
- 2.Will changing the direction of either the magnetic field or the current reverse the force acting on a conductor?
- 3.Is the self-inductance of a coil defined as the electromotive force (in volts) induced when the current changes at a rate of one Weber-turn per second?
- 4.Which component in a circuit resists changes in the current flow?
- 5.A coil is wrapped around an iron core carrying a current I. Which factor does NOT influence the self-induced voltage in the coil?
- 6.What is the effect of a fracture in the magnetic core of an inductor?
- 7.The coupling coefficient between two air-core inductors is determined by which of the following?
- 8.A coil generates an induced voltage of 350 mV when the current varies at a rate of 1 A/s. What is the inductance of the coil?
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