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- Subject
- Electronic instrumentselectrical-engineering-mcqs › electronic-instruments
- Published
- 22 Dec 2018
- Last updated
- 28 May 2026
Explanation
The internal resistance of a multimeter is calculated by multiplying its sensitivity (ohms per volt) by the full-scale voltage. Here, 1000 Ω/V × 50 V equals 50,000 Ω or 50 kilo-ohms.
More Electronic instruments MCQs
Practice related questions from the same subject.
- 1.An ammeter with a resistance of G ohms and a maximum current range of I amperes needs to be modified to measure up to n times the original current (nI). What should be the value of the resistance connected in parallel to achieve this new range?
- 2.What parameters can a Cathode Ray Oscilloscope (CRO) measure?
- 3.A voltmeter with an internal resistance of G ohms and a voltage range of V volts needs to be modified to measure up to nV volts. What resistance should be connected in series to achieve this new range?
- 4.Which device among the following typically exhibits the highest electrical resistance?
- 5.What is the resistance value of a perfect voltmeter?
- 6.What should be the value of the shunt resistance if a galvanometer with resistance G is to carry only 2% of the total current?
- 7.Which type of waveform is applied to the horizontal plates of a CRO to display the signal waveform properly?
- 8.What is the resistance value of an ideal ammeter?
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