A power source provides a maximum current of 0.5 A at its full-load voltage of 20 V. What is the smallest load resistance that can be safely connected to this power supply?

Regulated D.C. Power Supply MCQs for PPSC, FPSC, NTS, and Pakistan government job tests. Select an option below, then read the explanation.

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Subject
Regulated D.C. Power Supplyelectrical-engineering-mcqs › regulated-d-c-power-supply
Published
22 Dec 2018
Last updated
28 May 2026

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Explanation

To find the minimum load resistance, use Ohm's law: R = V / I. Given voltage (V) is 20 V and maximum current (I) is 0.5 A, so R = 20 / 0.5 = 40 ohms. Therefore, the smallest load resistance that can be connected without exceeding the current rating is 40 ohms.

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