A canal has a trapezoidal cross-section with the top width measuring 10 meters and the bottom width measuring 6 meters. If the cross-sectional area is 640 square meters, what is the depth of the canal?

Explanation

The area of a trapezium is given by (1/2) × (sum of parallel sides) × height. Here, the parallel sides are 10 m and 6 m, and the area is 640 sq m. Let the depth be h. So, (1/2) × (10 + 6) × h = 640 => 8 × h = 640 => h = 80 meters.