A pile of coconuts is split into groups of 2, 3, and 5, and in each case, there is exactly one coconut left over. What is the smallest number of coconuts in the pile?

Explanation

The least common multiple (LCM) of 2, 3, and 5 is 30. Since there is one coconut left after dividing by each of these numbers, the smallest number of coconuts is 30 + 1 = 31.