A rectangle has a perimeter of 60 meters. If its length is double its width, what is the area of the rectangle?

Explanation

Let the width be x meters, so the length is 2x meters. The perimeter is given by 2(length + width) = 60, which means 2(2x + x) = 60. Simplifying, 6x = 60, so x = 10. Therefore, the length is 20 meters and the width is 10 meters. The area is length × width = 20 × 10 = 200 square meters.