A rectangular pit with dimensions 5 m by 4.5 m by 2.1 m is excavated in the middle of a field that measures 13.5 m by 12.5 m. If the soil removed from the pit is evenly spread over the remaining area of the field, by how much will the ground level rise?

Explanation

The volume of earth dug out from the pit is calculated by multiplying its length, width, and depth (5 × 4.5 × 2.1 m). This volume is then spread uniformly over the remaining area of the field (total field area minus pit area). Dividing the volume by this remaining area gives the height by which the soil raises the field's surface, which is approximately 4.2 cm.