A trader has three quantities of milk: 435 liters, 493 liters, and 551 liters. What is the minimum number of identical-sized containers needed to store all the milk separately without mixing?

Explanation

To find the smallest number of equal-sized containers, first determine the highest common factor (HCF) of 435, 493, and 551, which is 29. Dividing each quantity by 29 gives the number of containers needed: (435/29) + (493/29) + (551/29) = 15 + 17 + 19 = 51.