A wire is initially shaped as a circle with a radius of 3.5 meters. It is then reshaped into a rectangle where the length and width maintain a ratio of 6 to 5. What is the area of this rectangle?

Explanation

The length of the wire remains constant, so the circumference of the original circle equals the perimeter of the rectangle. Let the length be 6x and the width be 5x. Then, 2(6x + 5x) = 2 * (22/7) * 3.5. Solving gives x = 1, so length = 6 cm and width = 5 cm. The area of the rectangle is length × width = 6 × 5 = 30 cm².