An AC circuit has an apparent power of 10 kVA and an active power of 8 kW. What is the reactive power in this circuit?

Explanation

The reactive power (Q) can be found using the relationship: S² = P² + Q², where S is apparent power and P is active power. Given S = 10 kVA and P = 8 kW, Q = √(S² - P²) = √(10² - 8²) = √(100 - 64) = √36 = 6 kVAR.