An AC circuit has an apparent power of 40 kVA with a power factor of 0.8 lagging. What is the real power consumed by this circuit?

Explanation

The real power (P) in an AC circuit is calculated by multiplying the apparent power (S) by the power factor (pf). Given S = 40 kVA and pf = 0.8, real power P = 40 × 0.8 = 32 kW. Therefore, the circuit consumes 32 kilowatts of real power.