Find three consecutive odd numbers arranged in ascending order where the sum of the last two numbers exceeds the first number by 13. What are these numbers?

Explanation

Let the three consecutive odd integers be x, x + 2, and x + 4. According to the problem, (x + 2) + (x + 4) = x + 13. Simplifying, 2x + 6 = x + 13, which gives x = 7. Therefore, the three numbers are 7, 9, and 11.