Given the quadratic equations I. x² + 11x + 30 = 0 and II. y² + 15y + 56 = 0, what is the correct relationship between the values of x and y after solving both equations?

Explanation

For equation I: x² + 11x + 30 = 0 can be factored as (x + 6)(x + 5) = 0, giving solutions x = -6 and x = -5. For equation II: y² + 15y + 56 = 0 factors to (y + 8)(y + 7) = 0, so y = -8 and y = -7. Comparing the roots, the smallest x (-6) is greater than the largest y (-7), so x > y.