How many distinct arrangements are possible for six players standing in a row if Asim and Raheem must not be positioned next to each other?

Explanation

There are 6 players, so the total number of ways to arrange them is 6! = 720. When Asim and Raheem stand together, treat them as a single unit, resulting in 5! arrangements. Since Asim and Raheem can switch places within this unit, multiply by 2, giving 5! × 2 = 240. Subtracting these from the total arrangements yields 720 - 240 = 480 ways where Asim and Raheem are not adjacent.