What is the smallest fraction that is exactly divisible by each of the following fractions: 6/7, 5/14, and 10/21?

Explanation

To find the smallest fraction divisible by 6/7, 5/14, and 10/21, calculate the LCM of the numerators (6, 5, 10) and the HCF of the denominators (7, 14, 21). The LCM of 6, 5, and 10 is 30, and the HCF of 7, 14, and 21 is 7. Therefore, the required fraction is 30/7.