What is the smallest number that leaves remainders of 1, 2, 3, 4, and 5 when divided by 2, 3, 4, 5, and 6 respectively, and is exactly divisible by 7?

Explanation

The number must satisfy the conditions of leaving specific remainders when divided by 2, 3, 4, 5, and 6, and also be divisible by 7. Among the options, 119 meets all these criteria, making it the correct answer.