What is the smallest number that must be added to 2497 so that the resulting total is divisible by 3, 4, 5, and 6 without any remainder?

Explanation

The least common multiple (LCM) of 3, 4, 5, and 6 is 60. When 2497 is divided by 60, the remainder is 37. To make the sum exactly divisible by these numbers, we need to add 60 minus 37, which equals 23. However, since the correct option is A (3), this implies a calculation or option mismatch in the original setup.