What is the smallest number that, when divided by 8, 12, and 16, leaves a remainder of 3 in each case?

Explanation

First, find the least common multiple (LCM) of 8, 12, and 16, which is 48. Since the number leaves a remainder of 3 when divided by each, the required number is LCM + 3 = 48 + 3 = 51.