What is the smallest number that, when reduced by 7, is divisible by 21, 28, 36, and 45?
Explanation
First, find the least common multiple (LCM) of 21, 28, 36, and 45, which is 1260. The required number is 7 more than this LCM, so 1260 + 7 = 1267.
First, find the least common multiple (LCM) of 21, 28, 36, and 45, which is 1260. The required number is 7 more than this LCM, so 1260 + 7 = 1267.