What is the smallest perfect square number that is divisible by 21, 36, and 56 without any remainder?

Explanation

To find the smallest perfect square divisible by 21, 36, and 56, first determine the least common multiple (LCM) of these numbers. The LCM is 3528, which is not a perfect square. To make it a perfect square, multiply by the necessary factors to balance the prime exponents. The resulting smallest perfect square divisible by all three numbers is 7056.