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- Problems on L.C.M and H.C.Fmathematics-mcqs › problems-on-l-c-m-and-h-c-f
- Published
- 12 Jul 2019
- Last updated
- 28 May 2026
Explanation
To find when they meet at the starting point simultaneously, calculate the time each takes to complete one lap: 11/4, 11/5, and 11/8 hours. The meeting time is the least common multiple (LCM) of these lap times. Multiplying each by 40 (the LCM of denominators 4, 5, and 8) gives 110, 88, and 55 respectively. The LCM of 110, 88, and 55 is 440. Dividing back by 40 results in 11 hours. Therefore, they will all meet again at the start after 11 hours.
More Problems on L.C.M and H.C.F MCQs
Practice related questions from the same subject.
- 1.What is the smallest perfect square that is divisible by 10, 12, 15, and 18?
- 2.What is the smallest number that leaves remainders of 1, 2, 3, 4, and 5 when divided by 6, 7, 8, 9, and 10 respectively, and is also exactly divisible by 19?
- 3.What is the smallest multiple of 13 that, when divided by 6, 8, and 12, leaves remainders of 5, 7, and 11 respectively?
- 4.What is the smallest number that leaves remainders of 1, 2, 3, 4, and 5 when divided by 2, 3, 4, 5, and 6 respectively, and is exactly divisible by 7?
- 5.A pile of stones can be evenly divided into groups of 21 without any remainder. However, when the stones are grouped into sets of 16, 20, 25, or 45, there are always 3 stones left over. What is the smallest possible number of stones in the pile?
- 6.What is the largest four-digit number that leaves remainders of 4, 9, 15, and 22 when divided by 10, 15, 21, and 28 respectively?
- 7.What is the smallest number that leaves a remainder of 25 when divided by 35, a remainder of 15 when divided by 25, and a remainder of 5 when divided by 15?
- 8.Find the smallest number that, when divided by 8, 12, 18, and 24, leaves remainders of 4, 8, 14, and 20 respectively.
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