What is the smallest number that leaves remainders of 1, 2, 3, 4, and 5 when divided by 2, 3, 4, 5, and 6 respectively, and is exactly divisible by 7?

Problems on L.C.M and H.C.F MCQs for PPSC, FPSC, NTS, and Pakistan government job tests. Select an option below, then read the explanation.

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Problems on L.C.M and H.C.Fmathematics-mcqs › problems-on-l-c-m-and-h-c-f
Published
12 Jul 2019
Last updated
28 May 2026

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Explanation

The number must satisfy the conditions of leaving specific remainders when divided by 2, 3, 4, 5, and 6, and also be divisible by 7. Among the options, 119 meets all these criteria, making it the correct answer.

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