A thermally transparent material reflects 40% of the incoming radiant energy on its surface. If the material's transmissivity is 0.15, what is the emissivity of its surface?

Heat Transfer MCQs for PPSC, FPSC, NTS, and Pakistan government job tests. Select an option below, then read the explanation.

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Subject
Heat Transfermechanical-engineering-mcqs › heat-transfer
Published
24 Jan 2019
Last updated
28 May 2026

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Explanation

Since the surface reflects 40% and transmits 15% of the incident radiant energy, the remaining portion must be absorbed. Emissivity is equal to absorptivity for a surface in thermal equilibrium, so emissivity = 1 - (reflectivity + transmissivity) = 1 - (0.40 + 0.15) = 0.45.

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